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Mysql num rows expects parameter 1 to be resource boolean error

Please edit it for me. Cause I am newbie so I don' t know. Your mysql_ query return false if it fails. " For SELECT, SHOW, DESCRIBE, EXPLAIN and other statements returning resultset, mysql_ query( ) returns a resource on success, or FALSE on error. I suspect you mean SELECT * FROM user. , not SELECT * FROM $ user. ( remove the $ ), which is causing your error. mysql_ query( ) returns false if the query failed, which is what you would expect if $ user doesn' t contain. mysql_ num_ rows( ) expects parameter 1 to be resource error. Here is the error message : Warning: mysql_ num_ rows( ) expects parameter 1 to be resource, boolean given in C: \ xampp\ htdocs\ test\ girisyap. From mysql_ query PHP public documentation: Return Values. For SELECT, SHOW, DESCRIBE, EXPLAIN and other statements returning resultset, mysql_ query( ) returns a resource on success, or FALSE on t mysql_ num_ rows ( resource $ result ) Retrieves the number of rows from a result set.

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    Rows mysql parameter

    This command is only valid for statements like SELECT or SHOW that return an actual result set. To retrieve the number of rows / > \ n" ) ; / / mysql error number rarely adds enough information to be worth including / / select the database. mysql_ num_ rows( $ result) ; / / Instead $ resultcount = mysql_ affected_ rows( $ result) ; if ( $ resultcount = = 1). That' s because mysql_ query sometimes returns boolean false ( query error). You need to check it: $ amn = mysql_ query( " SELECT * FROM ` Messages` WHERE to_ user= ' $ usr' AND read= ' 0' " ) ; if( $ amn = = = false). SQLの構築に失敗しているようです。 これを $ query = " SELECT * FROM users WHERE" ;. WHEREの後ろに半角スペースを入れてください。 $ query = " SELECT * FROM users WHERE " ;. The mysql_ query is returning a boolean value meaning the sql query is probably failing and you' re getting a false returned rather than a mysql resource. Have you checked your query?